t^2+3t+6=-3t-4

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Solution for t^2+3t+6=-3t-4 equation: 



t^2+3t+6=-3t-4

We move all terms to the left:

t^2+3t+6-(-3t-4)=0

We get rid of parentheses

t^2+3t+3t+4+6=0

We add all the numbers together, and all the variables

t^2+6t+10=0

a = 1; b = 6; c = +10;
Δ = b2-4ac
Δ = 62-4·1·10
Δ = -4
Delta is less than zero, so there is no solution for the equation

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